(3z-5)(z^2+4z+2)=

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Solution for (3z-5)(z^2+4z+2)= equation:


Simplifying
(3z + -5)(z2 + 4z + 2) = 0

Reorder the terms:
(-5 + 3z)(z2 + 4z + 2) = 0

Reorder the terms:
(-5 + 3z)(2 + 4z + z2) = 0

Multiply (-5 + 3z) * (2 + 4z + z2)
(-5(2 + 4z + z2) + 3z * (2 + 4z + z2)) = 0
((2 * -5 + 4z * -5 + z2 * -5) + 3z * (2 + 4z + z2)) = 0
((-10 + -20z + -5z2) + 3z * (2 + 4z + z2)) = 0
(-10 + -20z + -5z2 + (2 * 3z + 4z * 3z + z2 * 3z)) = 0
(-10 + -20z + -5z2 + (6z + 12z2 + 3z3)) = 0

Reorder the terms:
(-10 + -20z + 6z + -5z2 + 12z2 + 3z3) = 0

Combine like terms: -20z + 6z = -14z
(-10 + -14z + -5z2 + 12z2 + 3z3) = 0

Combine like terms: -5z2 + 12z2 = 7z2
(-10 + -14z + 7z2 + 3z3) = 0

Solving
-10 + -14z + 7z2 + 3z3 = 0

Solving for variable 'z'.

The solution to this equation could not be determined.

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